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Binary System:

Base: 2
Digits: 0, 1
Example: 27 (decimal) = 11011 (binary)

Decimal System:
Base: 10
Digits: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

Binary 2 Decimal conversion Example

Transform 110101 (binary) into decimal number
111001 = 1*(2^5)+ 1*(2^4) + 1*(2^3) + 0*(2^2) + 0*(2^1) + 1*(2^0) = 32 + 16+ 8 +0 +0+1 = 57

int convert_bin2dec(char *binstring)
{
  int j=0,sum=0,tmp;
  int len = strlen(binstring);
 
  for(j=0;j<len;j++)
  {
    if(binstring[j]!='1' && binstring[j]!='0')
    {
      printf("not a binary no");
      return -1;
    }
  }
 
  tmp = len-1;
  for(j=0; j<len; j++)
  {
    sum=sum+((binstring[j]-'0')*(tmp?(2<<tmp-1):1));
    tmp - -;
  }
  return sum;
}
 
#ifdef TEST
int main()
{
  char str[20]="10000000000";
  printf("%d\n", convert_bin2dec(str));
}
#endif

download binary to decimal conversion program [binary_to_decimal.c]

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Related Blog Items

• Binary decimal conversion....
• IEEE 754 Binary Floating Point Representation
• Convert integer to binary string
• Binary Search Trees
• Binary Streams Utility Classes

This entry was written by Shashavali Doodekula and posted on December 17, 2006 at 1:04 pm and filed under C Tidbits, C++ Tidbits, Conversions, Miscellaneous. Bookmark the permalink. Follow any comments here with the RSS feed for this post. Post a comment or leave a trackback: Trackback URL.